Q: What is the total or count of factors of the number 431,122,120?

A: 256

How do I find the total factors of the number 431,122,120?

Step 1

Find the prime factorization of the number 431,122,120.

Use a factor tree to assist with solving. Take a look at our prime factorization page for additional help.

Factor Tree

	431,122,120

2		215,561,060

	2		107,780,530

		2		53,890,265

			5		10,778,053

				11		979,823

					13		75,371

						23		3,277

							29		113

The prime factorization in exponential form is: 2³ x 5¹ x 11¹ x 13¹ x 23¹ x 29¹ x 113¹

Step 2

Setup the equation for determining the number of factors or divisors. The equation is:

d(n) = (a + 1)(b + 1)(c + 1)(d + 1)(e + 1)(f + 1)(g + 1)

Where d(n) is equal to the number of divisors of the number and a, b, etc. are equal to the exponents of the prime factorization.

Now substitute the letters in the equation with the the exponents of your prime factorization and then solve to calculate the total number of divisors.

431,122,120 = 2³ x 5¹ x 11¹ x 13¹ x 23¹ x 29¹ x 113¹

d(n) = (a + 1)(b + 1)(c + 1)(d + 1)(e + 1)(f + 1)(g + 1)

d(431122120) = (3 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1)

d(431122120) = (4)(2)(2)(2)(2)(2)(2)

d(431122120) = 256

More numbers for you to try

Take a look at the factors page to see the factors of 431,122,120 and how to find them.

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